How do you find the derivative of the function $y = arccos(e^(5x))$ ?

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Answer 1 · 2018-05-29T17:57:15

$y'(x)=-1/sqrt(1-(e^(5x))^2)*exp(5x)*5$

Note that

$(arc cos(x))'=-1/sqrt(1-x^2)$
then we get by the chain rule

$y'(x)=-1/sqrt(1-(e^(5x))^2)*5*e^(5x)$

How do you find the derivative of the function y = arccos(e^(5x))y = arccos(e^(5x))?