How do you find the derivative of the function: y = arccos[e^(2x)]?
1 Answer
Jan 20, 2016
Explanation:
Using the arccosine formula in conjunction with the chain rule:
d/dx[arccos(u)]=-(u')/sqrt(1-u^2)
Thus,
y'=-(d/dx[e^(2x)])/sqrt(1-(e^(2x))^2)=-(2e^(2x))/sqrt(1-e^(4x))
