How do you find the derivative of the function $f(x)=arcsin(4x)+arccos(4x)$ ?

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Answer 1 · 2015-05-14T10:24:29

Since the derivative of

$y=arcsin4x$

is

$y'=1/sqrt(1-16x^2)*4$

and the derivative of

$y=arccos4x$

is

$y'=-1/sqrt(1-16x^2)*4$ ,

The derivative of the function is $0$ .

How do you find the derivative of the function f(x)=arcsin(4x)+arccos(4x)f(x)=arcsin(4x)+arccos(4x)?