How do you find the derivative of the function: $arccos(x^2)$ ?

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Answer 1 · 2016-04-26T19:00:59

$theta =arccos(x^2)$

$cos(theta) = x^2$

$-theta'sin(theta) = 2x$

$theta' = -(2x)/sin(theta)$

don't forget that $sin(theta) = sqrt(1-cos^2(theta))$ and that $cos(theta) = x^2$

so we have

$theta' = -(2x)/sqrt(1-x^4)$

How do you find the derivative of the function: arccos(x^2)arccos(x^2)?