How do you find the derivative of the function: arccos (e^(2x))? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Massimiliano Apr 29, 2015 The derivative of y=arccosf(x) is y'=-1/sqrt(1-[f(x)]^2)*f'(x), so: y'=-1/sqrt(1-e^(4x))*2e^(2x). Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 5349 views around the world You can reuse this answer Creative Commons License