How do you find the derivative of Inverse trig function #y = tan(x + sec x)#?
1 Answer
Aug 26, 2015
Explanation:
All you really need to use in order to differentiate this function is the chain rule for
#color(blue)(d/dx(tanx) = sec^2x)" "# and#" "color(blue)(d/dx(secx) = secx * tanx)#
So, the derivative of
#d/dx(y) = d/(du)(tanu) * d/dx(u)#
#y^' = sec^2u * d/dx(x + secx)#
#y^' = sec^2u * (1 + secxtanx)#
#y^' = color(green)(sec^2(x+secx) * (1 + secxtanx))#
