How do you find the derivative of Inverse trig function #y = sin cos(3x -2)#?
1 Answer
Sep 25, 2015
Use the chain rule.
Explanation:
To find the derivative of
# = cos(cos(3x -2))[-sin(3x-2)d/dx(3x-2)]#
# = cos(cos(3x -2))[-sin(3x-2)(3)]#
# = -3sin(3x-2)cos(cos(3x -2))#
