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How do you find the derivative of #G(x)=int (tan(t^2))dt# from #[1,x^2]#?

1 Answer

Jul 22, 2018

#G(x)=int tant^2 \ dt qquad [1,x^2]#

# "ie " G(x)=int_1^(x^2) tant^2 \ dt #

From the FTC:

# G'(x)= tan((x^2)^2) (x^2)' = 2x \ tan x^4 #

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