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How do you find the derivative of #f(x) = 3x^2 ln 2x#?

1 Answer

Mar 17, 2018

#f'(x)=(dy)/(dx)=6xln2x+3x#

Explanation:

we need to use the product rule

#d/(dx)(color(red)(u)v)=vcolor(red)((du)/(dx))+color(red)(u)(dv)/(dx)#

#d/(dx)(color(red)(3x^2)ln2x)#

#(dy)/(dx)=ln2xcolor(red)(d/(dx)(3x^2))+color(red)(3x^2)d/(dx)(ln2x)#

#(dy)/(dx)=ln2x xxcolor(red)( 6x)+color(red)(3x^2) xx 1/(2x)xx2#

#(dy)/(dx)=6xln2x+3x#

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