How do you find the derivative of $arcsin(x/3)$ ?

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Answer 1 · 2017-02-22T18:11:34

See below

Let $y=arcsin(x/3)$

$siny=x/3$

$cosydy/dx=1/3$

$dy/dx=1/(3cosy)=1/(3sqrt(1-(x/3)^2))$

The general rule is for $f:x|->b arcsinx$ , $f'(x)=1/sqrt(1-x^2)b$

How do you find the derivative of arcsin(x/3)arcsin(x/3)?