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How do you find the derivative of #(29arctanx)^(1/2)#?

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Apr 21, 2015

Let y= #(29arctanx)^(1/2)#

#y^2= 29 arctanx#. Now differentiate w.r.t x

#2ydy/dx= 29/(1+x^2)#

#dy/dx= 29/{2(1+x^2)} 1/(29arctanx)^(1/2)#

=#sqrt29/[2(1+x^2) (arctanx)^(1/2)]#

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