How do you find the definite integrals for the lengths of the curves, but do not evaluate the integrals for #y=x^3, 0<=x<=1#?
1 Answer
Mar 14, 2018
Explanation:
Recall that the arc length of a curve is given by
#A = int_a^b sqrt(1 + (dy/dx)^2)dx#
Here this would be
#A = int_0^1 sqrt(1 + (3x^2)^2)dx#
#A = int_0^1 sqrt(1 + 9x^4)dx#
Hopefully this helps!
