How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

Question

How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

1 Answer

Impact of this question

3441 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-11T22:26:25

#int_0^2(1-2x-3x^2)d x=-10#

Explanation:

#int_0^2(1-2x-3x^2)d x=|x-2*1/2*x^2-3*1/3*x^3|_0^2#
#int_0^2(1-2x-3x^2)d x=|x-x^2-x^3|_0^2#
#int_0^2(1-2x-3x^2)d x=2-2^2-2^3#
#int_0^2(1-2x-3x^2)d x=2-4-8#
#int_0^2(1-2x-3x^2)d x#
#int_0^2(1-2x-3x^2)d x=-10#

Science

Math

Humanities

... and beyond

How do you find the definite integral of #int (1-2x-3x^2)dx# from #[0,2]#?

1 Answer

Explanation:

Related questions

Impact of this question