How do you find the definite integral of 2/(sqrt(x) *e^-sqrt(x)) from [1, 4]?
1 Answer
Oct 10, 2016
Explanation:
I=int_1^4 2/(sqrtx*e^(-sqrtx))dx
Simplify the negative exponent by bringing it to the numerator.
I=2int_1^4e^sqrtx/sqrtxdx
We will use the substitution
I=4int_1^4e^sqrtx/(2sqrtx)dx=4int_1^2e^udu
The integral
I=4[e^u]_1^2=4(e^2-e^1)=4e^2-4e