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How do you find the cross product a × b given #a = ‹t,t^2,t^3›#, #b = ‹1, 6t, 8t^2› #?

1 Answer

A. S. Adikesavan

Apr 23, 2016

#a X b = < 2t^4, -7t^3, 5t^2 >#

Explanation:

If# a = < a_1. a_2, a_3 > and b = < b_1, b_2, b_3 >, a X b = < a_2b_3-a_3b_2, a_3b_1-a_1b_3, a_1b_2-a_2b_1 >#.

Here, #a X b = < 8t^4-6t^4, t^3-8t^3, 6t^2-t^2 >=< 2t^4, -7t^3, 5t^2 >#.

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