Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the critical points of #h'(x)=x^2+8x-9#?

1 Answer

May 22, 2018

Critical points of # h^'(x) # are # x=-9 and x =1#

Explanation:

#h^' (x) = x^2+8 x-9 =0 # or

# (x+9)(x-1)=0 :. x+9=0 or x =-9 # and

# x-1=0 :. x=1 :. #

Critical points of # h^'(x) # are # x=-9 and x =1# [Ans]

Related questions

See all questions in Identifying Stationary Points (Critical Points) for a Function

Impact of this question

1688 views around the world

You can reuse this answer
Creative Commons License