# How do you find the critical points for #xlnx# and the local max and min?

##### 1 Answer

Jun 27, 2017

The derivative of

#y' = 1(lnx) + x(1/x)#

#y' = lnx + 1#

The critical points occur when the derivative equals

#0 = lnx + 1#

#-1 = lnx#

#e^-1 = x#

The derivative is undefined at

Whenever

Here is a graphical confirmation.

graph{xlnx [-18.02, 18.01, -9.01, 9.01]}

Hopefully this helps!