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How do you find the critical points for $F(x) =xe^-x$ ?

1 Answer

Nov 8, 2015

$f(x)$ is differentiable everywhere, so the critical points will simply be the solution(s) to $f'(x)=0$

Explanation:

$f'(x)=e^-x(1-x)=0$

critical point at $1-x=0$ or $x=1$

hope that helped

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