How do you find the coordinates of the center of the circle #x^2 +y^2 -4x+ 6x =12#?

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How do you find the coordinates of the center of the circle #x^2 +y^2 -4x+ 6x =12#?

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Answer 1 · 2016-03-11T12:41:57

#r=7/2#

Explanation:

#x^2+y^2-4x+6x=12#
#x^2+y^2+2x-12=0#
#x^2+y^2+D x+E y+F=0#
#C(a,b) " center coordinates"#
#D=2" "E=0" "F=-12#
#a=-D/2=-2/2=-1#
#b=-E/2=0/2=0#
#r=1/2*sqrt(D^2+E^2-4*F)#
#r=1/2*sqrt((-1)^2+0+4*12)#
#r=1/2*sqrt(1+48)#
#r=1/2*sqrt 49#
#r=7/2#

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How do you find the coordinates of the center of the circle #x^2 +y^2 -4x+ 6x =12#?

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