How do you find the center and the length of the radius of #x^2 + (y+6)^2 = 16/25#?

1 Answer
mason m
Dec 6, 2015

Center: #(0,-6)#
Radius: #4/5#

Explanation:

This is in the standard form of a circle:

#(x-color(blue)h)^2+(y-color(red)k)^2=color(green)r^2#

where: #(color(blue)h,color(red)k)# is the radius of the circle and #color(green)r# is the radius.

We can rewrite the original equation to match the standard form equation more clearly.

#(x-color(blue)0)^2+(y-(color(red)(-6)))^2=(color(green)(4/5))^2#

The circle has a center at #(0,-6)# and a radius length of #4/5#.

Related questions
See all questions in Identify Critical Points
Impact of this question
2041 views around the world
You can reuse this answer
Creative Commons License