How do you find the center and the length of the radius of $x^2 + y^2 = 121$ ?

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Answer 1 · 2018-05-13T19:27:44

$"centre "(0,0)$

$r=11$

the standard equation of a circle centre $( a,b)$ and radius $r$

$(x-a)^2+(y-b)^2=r^2$

for

$x^2+y^2=121$

the centre is $(0,0)$

radius $r=sqrt121=11$

How do you find the center and the length of the radius of x^2 + y^2 = 121x^2 + y^2 = 121?