How do you find the center and the length of the radius of #x^2 + y^2 = 121#?

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Answer 1 · 2018-05-13T19:27:44

#"centre "(0,0)#

#r=11#

the standard equation of a circle centre #( a,b)# and radius #r#

#(x-a)^2+(y-b)^2=r^2#

for

#x^2+y^2=121#

the centre is #(0,0)#

radius#r=sqrt121=11#