How do you find the center and radius of the circle #(x-4)^2 + (y)^2 = 25#?
1 Answer
May 22, 2016
centre (4 ,0) , r = 5
Explanation:
The equation of a circle in standard form is.
#color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))#
where (a ,b) is the centre and r ,the radius.For
#(x-4)^2+y^2=25# by comparison with standard a = 4 , b = 0 and r = 5
#rArr"centre"=(4,0)" and radius"=5#
