How do you find the center and radius of the circle #( x - 3 )^ 2 + y^2 = 4#?
1 Answer
Mar 5, 2017
Explanation:
The standard form of the
#color(blue)"equation of a circle"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
where (a ,b) are the coordinates of the centre and r, the radius.
#rArr(x-3)^2+(y-0)^2=2^2" is in this form"#
#rArr"centre "=(3,0)" and radius "=2#
