How do you find the center and radius of the circle #x^2 + y^2 − 10x + 8y + 32 = 0#?

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How do you find the center and radius of the circle #x^2 + y^2 − 10x + 8y + 32 = 0#?

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Answer 1 · 2016-10-16T18:42:15

The center is #(5,-4)# and the radius is 3

Explanation:

#x^2-10x+y^2+8y+32=0#
Completing the squares
#x^2-10x+25+y^2+8y+16=-32+25+16#
#(x-5)^2+(y+4)^2=9=3^2#
So the center is #(5,-4)# and the radius is 3
See the graph below
graph{x^2-10x+y^2+8y+32=0 [-20, 20, -10, 10]}

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How do you find the center and radius of the circle #x^2 + y^2 − 10x + 8y + 32 = 0#?

1 Answer

Explanation:

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