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How do you find the average rate of change for the function #s(t)=4.5t^2# on the indicated intervals [6,6+h]?

1 Answer

Konstantinos Michailidis

Sep 13, 2015

It is #4.5*(h+12)#

Explanation:

It is

#(Δs)/(Δt)=(s(6+h)-s(6))/(6+h-6)=4.5*((6+h)^2-6^2)/(6+h-6)= 4.5/h*(36+12h+h^2-36)=4.5*((h^2+12h)/h)=4.5*(h+12)#

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