How do you find the area of $△ A B C$ $triangle ABC$ given $C = 25^{\circ}, a = 4, b = 7$ $C=25^circ, a=4, b=7$ ?

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Answer 1 · 2017-01-09T09:11:14

$A = 5.92 s q . u n i t s (2 d p)$ $A=5.92" " sq. units(2 dp)$

One of the formulas for area of a triangle is:

$A = \frac{1}{2} \times a \times b \times sin C$ $A=1/2xxaxxbxxsinC$

In this case we have

$A = \frac{1}{2} \times 4 \times 7 \times sin 25$ $A=1/2xx4xx7xxsin25$

$A = 5.916655664$ $A=5.916655664$

$A = 5.92 s q . u n i t s (2 d p)$ $A=5.92" " sq."" units(2 dp)$

How do you find the area of triangle ABC△ABCtriangle ABC given C=25^circ, a=4, b=7C=25∘,a=4,b=7C=25^circ, a=4, b=7?