How do you find the area of $triangle ABC$ given b=9, c=16, sinA=5/6?

Question

1825 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-06T09:57:14

$60" sq.unit"$ .

Area of $DeltaABC=1/2bcsinA=1/2xx9xx16xx5/6=60" sq.unit"$ .

Answer 2 · 2018-03-06T10:10:32

$triangle=60$

We know that,area of $triangleABC=triangle=1/2bcsinA$
$:.triangle=1/2(9)(16)(5/6)=60$

How do you find the area of triangle ABCtriangle ABC given b=9, c=16, sinA=5/6?