How do you find the area of $triangle ABC$ given b=3, c=9, sinA=1/4?

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Answer 1 · 2016-12-04T17:00:37

3.375 square units

$Area (triangle ABC) = 1/2 bc sin A$

= $1/2 * 3 * 9 * 1/4$

= $27/8$

= $3 3/8$ or $3.375$

$A (triangle ABC$ )= $3.375$ square units

How do you find the area of triangle ABCtriangle ABC given b=3, c=9, sinA=1/4?