How do you find the area of $triangle ABC$ given b=14.6, c=12.8, $mangleA=56$ ?

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Answer 1 · 2017-07-29T07:25:10

$77.5$

$"Area of non right-angled triangle" = (a*b*sinC)/2$ , where:
$a = 14.6$
$b=12.8$
$C=56$

$(12.8*14.6*sin(56^circ))/2=77.4652708~~77.5$

How do you find the area of triangle ABCtriangle ABC given b=14.6, c=12.8, mangleA=56mangleA=56?