How do you find the area of triangle ABC given a=2, b=3, c=4?

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Answer 1 · 2017-07-23T09:42:40

The area is $=2.9u^2$

We apply Heron's formula

$area =sqrt(s(s-a)(s-b)(s-c))$

Where

$s=(a+b+c)/2$

Here,

$a=2$

$b=3$

$c=4$

Therefore,

$s=(2+3+4)/2=9/2=4.5$

So,

$area = sqrt (4.5*(4.5-2) * (4.5-3) * (4.5-4) )$

$=sqrt8.3475$

$=2.9u^2$

Where $u$ , represents the units in this case.