How do you find the area of $triangle ABC$ given $A=138^circ, b=10, c=20$ ?

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Answer 1 · 2017-01-24T07:08:18

$66.91sq.units(4dp).$

The Area of $Delta ABC=1/2bcsinA=(1/2)(10)(20)sin138^@$

$~~(100)(0.6691)=66.91sq.units(4dp).$

How do you find the area of triangle ABCtriangle ABC given A=138^circ, b=10, c=20A=138^circ, b=10, c=20?