How do you find the area of the triangle given b= 14, C= 110 degrees, B= 25 degrees?
1 Answer
Jun 16, 2015
Area of triangle: s = (1/2) bc.sin A
Explanation:
Angle A = 180 - B - C = 180 - 110 - 25 = 45 deg
sin C = sin 110 = 0.94; sin A = sin 45 = 0.707
sin B = sin 25 = 0.42.
b = 14; Find c
Area of triangle:
