How do you find the area given $a=5, b=7, c=10$ ?

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Answer 1 · 2017-04-19T16:20:47

Area of triangle is $16.25$

Given three sides $a,b$ and $c$ of a triangle, its are is given by $sqrt(s(s-a)(s-b)(s-c))$ , where $s=1/2(a+b+c)$ .

As $a=5$ , $b=7$ and $c=10$ , we have $s=1/2(5+7+10)=1/2×22=11$

Hence, area of triangle is $sqrt(11(11-5)(11-7)(11-10))$

= $sqrt(11×6×4×1)$

= $sqrt264=16.25$

How do you find the area given a=5, b=7, c=10a=5, b=7, c=10?