How do you find the arc length of the curve y=1+6x^(3/2)y=1+6x32 over the interval [0, 1]?
1 Answer
Mar 23, 2018
Use the arc length formula.
Explanation:
y=1+6x^(3/2)y=1+6x32
y'=9sqrtx
Arc length is given by:
L=int_0^1sqrt(1+81x)dx
Integrate directly:
L=2/243[(1+81x)^(3/2)]_0^1
Hence
L=2/243(82sqrt82-1)