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How do you find the antiderivative of #f(x)=4x^2-6x+7#?

1 Answer

Mar 7, 2017

#int f(x) dx = 4/3x^3-3x^2+7x+C#

Explanation:

#f(x) = 4x^2-6x+7#

#int f(x) dx = int (4x^2-6x+7)dx#

#= 4*int x^2 dx -6* int xdx+7* int 1dx#

Applying the power rule to each term:

#= (4x^3)/3 - (6x^2)/2 +(7x^1)/1 +C#

#= 4/3x^3-3x^2+7x+C#

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