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How do you find the antiderivative of #f(x)=1/5x^4-3/4x-1#?

1 Answer

Dec 21, 2017

#1/25x^(5)-3/8x^(2)-x+C#

Explanation:

Note #(a*1/(n+1)*x^(n+1))'=a*x^n#

#int1/5x^4-3/4x-1dx#

#1/5*1/(4+1)x^(4+1)-3/4*1/(1+1)x^(1+1)-x#

#1/5*1/(5)x^(5)-3/4*1/(2)x^(2)-x+C#

#1/25x^(5)-3/8x^(2)-x+C#

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