How do you find the angel between u=5i-4j, v=2i+j?

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How do you find the angel between u=5i-4j, v=2i+j?

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Answer 1 · 2016-10-15T13:00:22

Use the dot product definition
#u.v=∥u∥∥v∥cos(u,v)#
#cos(u,v)=(u.v)/(∥u∥∥v∥)#
#u.v=5*2-4*1=6#
#∥u∥=sqrt(5^2+4^2)=sqrt41#
#∥v∥=sqrt(2^2+1^2)=sqrt5#
#cos(u,v)=6/(sqrt41.sqrt5)=0.6266#
#(u,v)=0.894 rd#

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How do you find the angel between u=5i-4j, v=2i+j?

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