How do you find the 6 trigonometric functions for x = −π/3?

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How do you find the 6 trigonometric functions for x = −π/3?

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Answer 1 · 2015-09-23T04:08:34

Find the 6 trig functions of $(- \frac{π}{3})$ $(-pi/3)$

Explanation:

Trig table of Special Arcs gives -->
$sin (- \frac{π}{3}) = - sin (\frac{π}{3}) = - \frac{\sqrt{3}}{2}$ $sin (-pi/3) = - sin (pi/3) = - sqrt3/2$
$cos (- \frac{π}{3}) = cos (\frac{π}{3}) = \frac{1}{2}$ $cos (-pi/3) = cos (pi/3) = 1/2$
$tan (- \frac{π}{3}) = - tan (\frac{π}{3}) = - \sqrt{3}$ $tan (-pi/3) = - tan (pi/3) = - sqrt3$
$cot (- \frac{π}{3}) = - cot (\frac{π}{3}) = - \frac{\sqrt{3}}{3}$ $cot (-pi/3) = - cot (pi/3) = - sqrt3/3$
$sec (- \frac{π}{3}) = \frac{1}{cos} = 2$ $sec (-pi/3) = 1/(cos) = 2$
$csc (- \frac{π}{3}) = \frac{1}{sin} = - \frac{2 \sqrt{3}}{3}$ $csc (-pi/3) = 1/(sin) = - (2sqrt3)/3$

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How do you find the 6 trigonometric functions for x = −π/3?

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