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How do you find the 6 trigonometric functions for -pi/2?

1 Answer

Vinícius Ferraz

May 21, 2018

See below

Explanation:

#sin (-pi/2) = -1# and #cos(-pi/2) = 0#

#tan (-pi/2) = (-1)/0 = # undetermined

#cot (-pi/2) = 0/(-1) = 0#

#sec (-pi/2) = 1/0 = # undetermined

#cossec (-pi/2) = 1/(-1) = -1#

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