How do you find taylor polynomials of degree n approximating 5/(2-2x) for x near 0?
1 Answer
Jul 28, 2016
Explanation:
If
1/(1-x) = sum_(n=0)^oo x^n
Hence:
5/(2-2x) = 5/(2(1-x)) = 5/2*1/(1-x) = 5/2 sum_(n=0)^oo x^n = sum_(n=0)^oo 5/2x^n