How do you find slope, point slope, slope intercept, standard form, domain and range of a line for Line J (-3,4) (0,10)?

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Answer 1 · 2018-06-11T02:58:56

#"Slope " = 2, "Point - Slope form " y - 10 = 2x#

#"Slope - intercept form is " y = 2x + 10#

#"Standard form " 2x - y = -10#

#"Domain and Range " -oo to =oo#

#(x_1, y_1) = (-3,4), (x_2, y_2) = (0,10)#

#"1. Slope " m = (y_2 - y_1) / (x_2 - x_1) = (10-4) / (0 + 3) = 2#

#"2. Point - Slope form is " (y - y_1) = m (x - x_1)#

#(y - 10) = 2 * (x - 0) " or " y - 10 = 2x#

#"3. Slope - intercept form is " y = 2x + 10#

#"4. Standard form is " 2x - y = -10#

#"5. Domain is " - oo to +oo#

#"6. range is " - oo to +oo#