How do you find slope, point slope, slope intercept, standard form, domain and range of a line for Line D (3, -7) (9,-3)?

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How do you find slope, point slope, slope intercept, standard form, domain and range of a line for Line D (3, -7) (9,-3)?

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Answer 1 · 2018-01-24T11:19:40

Slope is $2/3$ , point slope form is $y+7=2/3(x-3)$ ,
slope-intercept form is $y= 2/3x-9.$ , standard form is
$2x-3y=27$ .Domain: $x in RR or (-oo,oo)$ . Range: $y in RR or (-oo,oo)$

Explanation:

The slope of the line passing through $(3,-7) and (9,-3)$ is

$m= (y_2-y_1)/(x_2-x_1)= (-3+7)/(9-3)=4/6=2/3$

Point slope form of the line is $y-y_1=m(x-x_1)$ or

$y+7=2/3(x-3)$

Let the equation of the line in slope-intercept form be $y=mx+c$

or $y=2/3x+c$ . The point (3,-7) will satisfy the equation . So,

$-7= 2/3*3+c or c= -7-2= -9$ . Hence the equation of

the line in slope-intercept form is $y= 2/3x-9.$

The equation of the line in standard form is $3y=2x-27$ or

$2x-3y=27$ .

Domain of the line $y= 2/3x-9.$ is any real value of $x$

Domain: $x in RR or (-oo,oo)$

Range of the line $y= 2/3x-9.$ is any real value of $y$

Range: $y in RR or (-oo,oo)$

graph{2/3x-9 [-40, 40, -20, 20]}

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How do you find slope, point slope, slope intercept, standard form, domain and range of a line for Line D (3, -7) (9,-3)?

1 Answer

Explanation:

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