How do you find #lim (x^2+4)/(x^2-4)# as #x->2#?

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How do you find #lim (x^2+4)/(x^2-4)# as #x->2#?

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Answer 1 · 2016-12-09T16:32:32

There is no such limit.

Explanation:

The function has vertical asymptotes at x =-2 and x = +2. Informally, #x to oo# as #x to 2#.

Furthermore, as #x to +-oo#, the function #to# 1, because the coefficients of the highest power of #x# in the numerator polynomial is the same as that in the denominator polynomial.

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How do you find #lim (x^2+4)/(x^2-4)# as #x->2#?

1 Answer

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