How do you find $h (x) = f (x) + g (x)$ $h(x)=f(x)+g(x)$ given $f (x) = - x - 5$ $f(x)=-x-5$ and $g (x) = {(x + 3)}^{2}$ $g(x)=(x+3)^2$ ?

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How do you find $h (x) = f (x) + g (x)$ $h(x)=f(x)+g(x)$ given $f (x) = - x - 5$ $f(x)=-x-5$ and $g (x) = {(x + 3)}^{2}$ $g(x)=(x+3)^2$ ?

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Answer 1 · 2018-08-04T10:01:46

$h (x) = x^{2} + 5 x + 4$ $h(x)=x^2+5x+4$

Explanation:

$h (x) = f (x) + g (x)$ $h(x)=f(x)+g(x)$

$h (x) = - x - 5 + x^{2} + 6 x + 9$ $color(white)(h(x))=-x-5+x^2+6x+9$

$h (x) = x^{2} + 5 x + 4$ $color(white)(h(x))=x^2+5x+4$

$h (x) = (x + 1) (x + 4) \leftarrow in factored form$ $color(white)(h(x))=(x+1)(x+4)larrcolor(blue)"in factored form"$

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How do you find $h (x) = f (x) + g (x)$ $h(x)=f(x)+g(x)$ given $f (x) = - x - 5$ $f(x)=-x-5$ and $g (x) = {(x + 3)}^{2}$ $g(x)=(x+3)^2$ ?

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How do you find h(x)=f(x)+g(x)h(x)=f(x)+g(x) given f(x)=−x−5f(x)=-x-5 and g(x)=(x+3)2g(x)=(x+3)^2?

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How do you find $h (x) = f (x) + g (x)$ $h(x)=f(x)+g(x)$ given $f (x) = - x - 5$ $f(x)=-x-5$ and $g (x) = {(x + 3)}^{2}$ $g(x)=(x+3)^2$ ?