How do you find $h(g(f(5)))$ given $f(x)=2x-1$ and $g(x)=3x$ and $h(x)=x^2+1$ ?

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Answer 1 · 2017-01-23T16:50:43

$730.$

By Defn., $h(g(f(5)))=h[g{f(5)}]$

So, we first need $f(5)=2(5)-1=9$

$rArr g(f(5))=g(9)=(3)(9)=27$

$rArr h[g{f(5)}]=h(27)=27^2+1=729+1=730.$

How do you find h(g(f(5)))h(g(f(5))) given f(x)=2x-1f(x)=2x-1 and g(x)=3xg(x)=3x and h(x)=x^2+1h(x)=x^2+1?