How do you find $(\frac{h}{g}) (a)$ $(h/g)(a)$ given $h (a) = 3 a$ $h(a)=3a$ and $g (a) = - a^{3} - 3$ $g(a)=-a^3-3$ ?

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Answer 1 · 2017-06-09T12:15:57

$(\frac{h}{g}) (a) = \frac{h (a)}{g (a)} = \frac{3 a}{- a^{3} - 3}$ $(h/g)(a) = (h(a))/(g(a)) = (3a)/(-a^3 - 3)$

How do you find (hg)(a)(h/g)(a) given h(a)=3ah(a)=3a and g(a)=−a3−3g(a)=-a^3-3?