How do you find $(g \cdot h) (x)$ $(g*h)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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How do you find $(g \cdot h) (x)$ $(g*h)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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Answer 1 · 2017-03-12T17:49:17

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Explanation:

$(g \cdot h) (x) = g (x) \cdot h (x) = (2 x - 3) \cdot (1 - 4 x)$ $(g * h)(x) = g(x) * h(x) = (2x - 3) * (1 -4x)$

$(g \cdot h) (x) = (2 x - 3) (1 - 4 x)$ $(g * h)(x) = (color(red)(2x - 3))(color(blue)(1 -4x))$

$(g \cdot h) (x) = (2 x \times 1) - (2 x \times 4 x) - (3 \times 1) + (3 \times 4 x)$ $(g * h)(x) = (color(red)(2x) xx color(blue)(1)) - (color(red)(2x) xx color(blue)(4x)) - (color(red)(3) xx color(blue)(1)) + (color(red)(3) xx color(blue)(4x))$

$(g \cdot h) (x) = 2 x - 8 x^{2} - 3 + 12 x$ $(g * h)(x) = 2x - 8x^2 - 3 + 12x$

$(g \cdot h) (x) = - 8 x^{2} + 2 x + 12 x - 3$ $(g * h)(x) = -8x^2 + 2x + 12x - 3$

$(g \cdot h) (x) = - 8 x^{2} + (2 + 12) x - 3$ $(g * h)(x) = -8x^2 + (2 + 12)x - 3$

$(g \cdot h) (x) = - 8 x^{2} + 14 x - 3$ $(g * h)(x) = -8x^2 + 14x - 3$

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How do you find $(g \cdot h) (x)$ $(g*h)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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How do you find (g*h)(x)(g⋅h)(x)(g*h)(x) given f(x)=x^2-1 and f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3 and and and h(x)=1-4x#?

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How do you find $(g \cdot h) (x)$ $(g*h)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?