How do you find $(g*h)(4)$ given $f(x)=x^2-1 and$ g(x)=2x-3 $and$ h(x)=1-4x#?

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Answer 1 · 2017-05-25T17:46:38

See a solution process below:

First, we can write $(g * h)(x)$ as:

$(g * h)(x) = (2x - 3) * (1 - 4x)$

Next, we can substitute $color(red)(4)$ for each occurrence of $color(red)(x)$ in $(g * h)(x)$ to find $(g * h)(4)$ :

$(g * h)(color(red)(x)) = (2color(red)(x) - 3) * (1 - 4color(red)(x))$ becomes:

$(g * h)(color(red)(4)) = ((2 xx color(red)(4)) - 3) * (1 - (4 xx color(red)(4)x))$

$(g * h)(color(red)(4)) = (8 - 3) * (1 - 16)$

$(g * h)(color(red)(4)) = 5 * -15$

$(g * h)(color(red)(4)) = -75$

How do you find (g*h)(4)(g*h)(4) given f(x)=x^2-1 and f(x)=x^2-1 and g(x)=2x-3 and and h(x)=1-4x#?