How do you find $g(f(h(-6)))$ given $f(x)=2x-1$ and $g(x)=3x$ and $h(x)=x^2+1$ ?

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Answer 1 · 2017-02-11T11:15:18

219

Since $h(-6)=(-6)^2+1=37$ , then

$g(f(h(-6)))=g(f(37))$

$f(37)=2*37-1=73$

therefore

$g(f(37))=g(73)=3*73=219$

How do you find g(f(h(-6)))g(f(h(-6))) given f(x)=2x-1f(x)=2x-1 and g(x)=3xg(x)=3x and h(x)=x^2+1h(x)=x^2+1?