How do you find $(f-g)(x)$ given $f(x)=x^2-1 and$ g(x)=2x-3 $and$ h(x)=1-4x#?

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Answer 1 · 2017-04-11T17:16:38

See the entire solution process below:

$(f - g)(x) = f(x) - g(x) = (x^2 - 1) - (2x - 3)$

$(f - g)(x) = x^2 - 1 - 2x + 3$

$(f - g)(x) = x^2 - 2x + 3 - 1$

$(f - g)(x) = x^2 - 2x + 2$

The $h(x)$ is not used and is extraneous and unnecessary information for this problem.

How do you find (f-g)(x)(f-g)(x) given f(x)=x^2-1 and f(x)=x^2-1 and g(x)=2x-3 and and h(x)=1-4x#?